What is the tangent of f(x)=9xe^x,(0,0) ?

The tangent of f(x)=9xe^x,(0,0) is y=9x

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tangent of f(x)=9xe^x,(0,0)

tangent of

f (x) = 9 x e^{x}, (0, 0)

y = 9 x

Solution steps

Find the slope of

f (x) = 9 x e^{x} : \frac{df ( x )}{d x} = 9 (e^{x} + e^{x} x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9

Find the line with slope m=

9

and passing through

(0, 0) : y = 9 x

y = 9 x

f (x) = \frac{1}{5} x^{4} - 4 x^{2} + 1

\frac{d}{d x} (\frac{3 x + 2}{2 x + 1})

(x + 1) y^{^{'}} = x + 6

\frac{\partial}{\partial x} (3 x^{4} - sin (5 x) + 4 x)

x \to - 2 lim (x + 2)

What is the tangent of f(x)=9xe^x,(0,0) ?
The tangent of f(x)=9xe^x,(0,0) is y=9x