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Popular >

(x+1)y^'=x+6

Solution

(x + 1) y^{^{'}} = x + 6

Solution

y = 5 ln (x + 1) + x + c_{1}

Solution steps

(x + 1) y^{'} (x) = x + 6

Isolate

y^{'} (x) : y^{'} (x) = \frac{x + 6}{x + 1}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{x + 6}{x + 1} d x

\int \frac{x + 6}{x + 1} d x = 5 ln (x + 1) + x + c_{1}

y = 5 ln (x + 1) + x + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (x+1)y^'=x+6 ?
The solution for (x+1)y^'=x+6 is y=5ln(x+1)+x+c_{1}