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Popular >

y^'=y(3-y)

Solution

y^{^{'}} = y (3 - y)

Solution

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

Solution steps

y^{'} (t) = y (3 - y)

Solve Bernoulli ODE:

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=y(3-y) ?
The solution for y^'=y(3-y) is y= 3/(-e^{-3t-c_{1)}+1}