What is area y=12-x^2,y=-3x-16 ?

The answer to area y=12-x^2,y=-3x-16 is 1331/6

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area y=12-x^2,y=-3x-16

area

y = 12 - x^{2}, y = - 3 x - 16

\frac{1331}{6}

Decimal

221.83333 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{7} 12 - x^{2} - (- 3 x - 16) d x

Solve

\int_{- 4}^{7} 12 - x^{2} - (- 3 x - 16) d x : \frac{1331}{6}

The area is:

= \frac{1331}{6}

(e^{2 x} \cdot 2)^{^{'}}

y (θ) = θ cos (θ)

6 x sin (x^{2})

y = 1 - x^{2}, y = x^{2} - 1

y^{^{''}} + 3 y^{^{'}} - 12 y = 0