What is the solution for y^'=(x^6)/y ?

The solution for y^'=(x^6)/y is y=sqrt((2x^7)/7+c_{1)},y=-sqrt((2x^7)/7+c_{1)}

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y^'=(x^6)/y

y^{^{'}} = \frac{x ^{6}}{y}

y = \frac{2 x ^{7}}{7} + c_{1}, y = - \frac{2 x ^{7}}{7} + c_{1}

Solution steps

y^{'} (x) = \frac{x ^{6}}{y}

Solve separable ODE:

y = \frac{2 x ^{7}}{7} + c_{1}, y = - \frac{2 x ^{7}}{7} + c_{1}

y = \frac{2 x ^{7}}{7} + c_{1}, y = - \frac{2 x ^{7}}{7} + c_{1}

\int x^{2} + 4 d x

\frac{d}{d y} ((y e^{3 y} + e^{5 y})^{9})

y = x^{2} + 6 x + 6, y = 1, x = - 5, x = 0

\int 2 csc^{3} (x) d x

(1 - x)^{2} \cdot b

What is the solution for y^'=(x^6)/y ?
The solution for y^'=(x^6)/y is y=sqrt((2x^7)/7+c_{1)},y=-sqrt((2x^7)/7+c_{1)}