What is the derivative of (1-x)^2*b ?

The derivative of (1-x)^2*b is -2b(1-x)

What is the first derivative of (1-x)^2*b ?

The first derivative of (1-x)^2*b is -2b(1-x)

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derivative of

(1 - x)^{2} \cdot b

- 2 b (1 - x)

Solution steps

\frac{d}{d x} ((1 - x)^{2} b)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} ((1 - x)^{2})

Apply the chain rule:

2 (1 - x) \frac{d}{d x} (1 - x)

= 2 (1 - x) \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= b \cdot 2 (1 - x) (- 1)

Simplify

= - 2 b (1 - x)

\frac{d}{d x} (2 x^{- 4})

\int x^{3} ln (5 x) d x

(x^{2} e^{x})^{^{'}}

y^{^{'}} + \frac{2 y}{x} = - \frac{4}{x}

\int_{0}^{1} \frac{9 y}{e ^{2 y}} d y

What is the derivative of (1-x)^2*b ?
The derivative of (1-x)^2*b is -2b(1-x)
What is the first derivative of (1-x)^2*b ?
The first derivative of (1-x)^2*b is -2b(1-x)