What is area y=x^2+6x+6,y=1,x=-5,x=0 ?

The answer to area y=x^2+6x+6,y=1,x=-5,x=0 is 13

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area y=x^2+6x+6,y=1,x=-5,x=0

area

y = x^{2} + 6 x + 6, y = 1, x = - 5, x = 0

13

Solution steps

Apply the area formula:

\int_{- 5}^{0} x^{2} + 6 x + 5 d x

Solve

\int_{- 5}^{0} x^{2} + 6 x + 5 d x : 13

The area is:

= 13

\int 2 csc^{3} (x) d x

(1 - x)^{2} \cdot b

\frac{d}{d x} (2 x^{- 4})

\int x^{3} ln (5 x) d x

(x^{2} e^{x})^{^{'}}

What is area y=x^2+6x+6,y=1,x=-5,x=0 ?
The answer to area y=x^2+6x+6,y=1,x=-5,x=0 is 13