What is the d/(dy)(A/(y^{11)}+Be^y) ?

The d/(dy)(A/(y^{11)}+Be^y) is -(11A)/(y^{12)}+Be^y

What is the first d/(dy)(A/(y^{11)}+Be^y) ?

The first d/(dy)(A/(y^{11)}+Be^y) is -(11A)/(y^{12)}+Be^y

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\frac{d}{d y} (\frac{A}{y ^{11}} + B e^{y})

- \frac{11 A}{y ^{12}} + B e^{y}

Solution steps

\frac{d}{d y} (\frac{A}{y ^{11}} + B e^{y})

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{A}{y ^{11}}) + \frac{d}{d y} (B e^{y})

\frac{d}{d y} (\frac{A}{y ^{11}}) = - \frac{11 A}{y ^{12}}

\frac{d}{d y} (B e^{y}) = B e^{y}

= - \frac{11 A}{y ^{12}} + B e^{y}

\int \frac{2 x ^{3} - 5 x ^{2} + x - 6}{x} d x

x \to 0 lim (\frac{16}{x ^{4}})

f (x) = \frac{1}{x + 6}

\frac{e ^{y} + e ^{- y}}{2}

\int e^{y^{2}} d y

What is the d/(dy)(A/(y^{11)}+Be^y) ?
The d/(dy)(A/(y^{11)}+Be^y) is -(11A)/(y^{12)}+Be^y
What is the first d/(dy)(A/(y^{11)}+Be^y) ?
The first d/(dy)(A/(y^{11)}+Be^y) is -(11A)/(y^{12)}+Be^y