What is the tangent of y=x^2-6x+7 ?

The tangent of y=x^2-6x+7 is y=(2a_{0}-6)x-a_{0}^2+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^2-6x+7

tangent of

y = x^{2} - 6 x + 7

y = (2 a_{0} - 6) x - a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 6 a_{0} + 7)

Find the slope of

y = x^{2} - 6 x + 7 : \frac{d y}{d x} = 2 x - 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a_{0} - 6

Find the line with slope m=

2 a_{0} - 6

and passing through

(a_{0}, a_{0}^{2} - 6 a_{0} + 7) : y = (2 a_{0} - 6) x - a_{0}^{2} + 7

y = (2 a_{0} - 6) x - a_{0}^{2} + 7

y^{^{''}} - 4 y = sin (2 t)

\int (x)^{\frac{1}{2}} d x

y = - 5 - 8 x^{2}, (5, - 205)

\frac{2}{1 - x}, 0

\frac{1}{1 + x ^{2}}, 0

What is the tangent of y=x^2-6x+7 ?
The tangent of y=x^2-6x+7 is y=(2a_{0}-6)x-a_{0}^2+7