What is the derivative of (x^2+2x^2) ?

The derivative of (x^2+2x^2) is 2(x^2+2x)(2x+2)

What is the first derivative of (x^2+2x^2) ?

The first derivative of (x^2+2x^2) is 2(x^2+2x)(2x+2)

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\frac{d}{d x} ((x^{2} + 2 x)^{2})

2 (x^{2} + 2 x) (2 x + 2)

Solution steps

\frac{d}{d x} ((x^{2} + 2 x)^{2})

Apply the chain rule:

2 (x^{2} + 2 x) \frac{d}{d x} (x^{2} + 2 x)

= 2 (x^{2} + 2 x) \frac{d}{d x} (x^{2} + 2 x)

\frac{d}{d x} (x^{2} + 2 x) = 2 x + 2

= 2 (x^{2} + 2 x) (2 x + 2)

\frac{\partial}{\partial x} (5 x^{8} y^{5} + 2 x^{4} y^{6})

\frac{d}{d x} (12 x^{3} cos (x^{4}))

f (x) = \frac{2}{1 - 8 x}

\int \frac{y ^{2}}{2} d y

\frac{\partial}{\partial x} (\frac{1}{2} x^{2})

What is the derivative of (x^2+2x^2) ?
The derivative of (x^2+2x^2) is 2(x^2+2x)(2x+2)
What is the first derivative of (x^2+2x^2) ?
The first derivative of (x^2+2x^2) is 2(x^2+2x)(2x+2)