What is the first d/(dt)((t^3)/3) ?

The first d/(dt)((t^3)/3) is t^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dt)((t^3)/3)

\frac{d}{d t} (\frac{t ^{3}}{3})

t^{2}

Solution steps

\frac{d}{d t} (\frac{t ^{3}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d t} (t^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} \cdot 3 t^{3 - 1}

Simplify

\frac{1}{3} \cdot 3 t^{3 - 1} : t^{2}

= t^{2}

2 x^{2} + x + 1

f (x) = 5 - 4 x^{2}

\frac{d}{d x} (2 x - \frac{2}{x})

\frac{d y}{d t} = - 0.0077 y

f (x) = tan (x + 1)