What is the integral from 0 to 27 of \sqrt[3]{x} ?

The integral from 0 to 27 of \sqrt[3]{x} is 243/4

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integral from 0 to 27 of \sqrt[3]{x}

\frac{243}{4}

Decimal Notation

60.75

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{27}

= [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{27}

Compute the boundaries:

\frac{243}{4}

= \frac{243}{4}

s \to \infty lim (c t)

x = y, x = 2, y = 0

\frac{d y}{d x} = \frac{1}{1 - x ^{2}}

\int_{0}^{1} \frac{26}{4 y - 1} d y

What is the integral from 0 to 27 of \sqrt[3]{x} ?
The integral from 0 to 27 of \sqrt[3]{x} is 243/4