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Popular >

area x=sqrt(y),x=2,y=0

Solution

area

x = y, x = 2, y = 0

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Isolate

y

for

x = y : y = x^{2} {x \geq 0}

Apply the area formula:

\int_{0}^{2} ∣ x ∣^{2} d x

Solve

\int_{0}^{2} ∣ x ∣^{2} d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Popular Examples

(dy)/(dx)= 1/(sqrt(1-x^2))

\frac{d y}{d x} = \frac{1}{1 - x ^{2}}

derivative of 2/(\sqrt[3]{x}+3cos(x))

integral from 0 to 1 of (26)/(4y-1)

\int_{0}^{1} \frac{26}{4 y - 1} d y

integral of (sec^2(x)tan(x))

\int (sec^{2} (x) tan (x)) d x

integral of x^5sqrt(12+x^6)

\int x^{5} 12 + x^{6} d x

Frequently Asked Questions (FAQ)

What is area x=sqrt(y),x=2,y=0 ?
The answer to area x=sqrt(y),x=2,y=0 is 8/3