What is the derivative of f(x)=ln(x+1) ?

The derivative of f(x)=ln(x+1) is 1/(x+1)

What is the first derivative of f(x)=ln(x+1) ?

The first derivative of f(x)=ln(x+1) is 1/(x+1)

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derivative of

f (x) = ln (x + 1)

\frac{1}{x + 1}

Solution steps

\frac{d}{d x} (ln (x + 1))

Apply the chain rule:

\frac{1}{x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{x + 1} \cdot 1

Simplify

= \frac{1}{x + 1}

x \to \infty lim (1 - \frac{2}{x})

\frac{d}{d x} (\frac{1}{( x + 2 )})

\int \frac{x ^{3}}{e ^{3 x^{4}}} d x

e^{x}, at x = 3

\int_{0}^{1} x^{3} 1 - x^{2} d x

What is the derivative of f(x)=ln(x+1) ?
The derivative of f(x)=ln(x+1) is 1/(x+1)
What is the first derivative of f(x)=ln(x+1) ?
The first derivative of f(x)=ln(x+1) is 1/(x+1)