What is the derivative of sin^2(t) ?

The derivative of sin^2(t) is sin(2t)

What is the first derivative of sin^2(t) ?

The first derivative of sin^2(t) is sin(2t)

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derivative of

sin^{2} (t)

sin (2 t)

Solution steps

\frac{d}{d t} (sin^{2} (t))

Apply the chain rule:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 2 sin (t) cos (t)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 t)

\frac{d}{d x} (\frac{x}{2 x + 3})

\int_{1}^{1 - 2 y} \frac{y}{x} d x

\frac{d}{d x} (9 x^{2} + y^{2})

y = 5 x^{2}, (4, 80)

x \to - \infty lim (- ln (x))

What is the derivative of sin^2(t) ?
The derivative of sin^2(t) is sin(2t)
What is the first derivative of sin^2(t) ?
The first derivative of sin^2(t) is sin(2t)