What is (\partial)/(\partial x)(-4(x+y^6)) ?

The answer to (\partial)/(\partial x)(-4(x+y^6)) is -4

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(\partial)/(\partial x)(-4(x+y^6))

\frac{\partial}{\partial x} (- 4 (x + y^{6}))

- 4

Solution steps

\frac{\partial}{\partial x} (- 4 (x + y^{6}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{\partial}{\partial x} (x + y^{6})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 4 (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y^{6}))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y^{6}) = 0

= - 4 (1 + 0)

Simplify

= - 4

(2 y + 1)^{3} - 24 x = - 3, (- 1, - 2)

\frac{\partial}{\partial x} (5 (x - 3)^{2})

\frac{d y}{d x} + 2 x y^{4} = 0

\frac{d}{d x} (\frac{1}{6 + x})

(1 + x^{2}) d y + (1 + y^{2}) d x = 0

What is (\partial)/(\partial x)(-4(x+y^6)) ?
The answer to (\partial)/(\partial x)(-4(x+y^6)) is -4