en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of (8x^3+2x^2)^4

Solution

derivative of

(8 x^{3} + 2 x^{2})^{4}

Solution

4 (8 x^{3} + 2 x^{2})^{3} (24 x^{2} + 4 x)

Solution steps

\frac{d}{d x} ((8 x^{3} + 2 x^{2})^{4})

Apply the chain rule:

4 (8 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (8 x^{3} + 2 x^{2})

= 4 (8 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (8 x^{3} + 2 x^{2})

\frac{d}{d x} (8 x^{3} + 2 x^{2}) = 24 x^{2} + 4 x

= 4 (8 x^{3} + 2 x^{2})^{3} (24 x^{2} + 4 x)

Popular Examples

integral from-4 to 4 of 16-x^2

\int_{- 4}^{4} 16 - x^{2} d x

(dy)/(dx)=5sqrt(y)

\frac{d y}{d x} = 5 y

21xy^'-ln(x^7)=0

21 x y^{^{'}} - ln (x^{7}) = 0

integral of (2x)/((x^2+5)ln(x^2+5))

\int \frac{2 x}{( x ^{2} + 5 ) ln ( x ^{2} + 5 )} d x

tangent of f(x)=9x^2-x^3,\at x=1 tangent of

f (x) = 9 x^{2} - x^{3}, at x = 1

Frequently Asked Questions (FAQ)

What is the derivative of (8x^3+2x^2)^4 ?
The derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)
What is the first derivative of (8x^3+2x^2)^4 ?
The first derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)