What is the derivative of (8x^3+2x^2)^4 ?

The derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)

What is the first derivative of (8x^3+2x^2)^4 ?

The first derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)

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derivative of

(8 x^{3} + 2 x^{2})^{4}

4 (8 x^{3} + 2 x^{2})^{3} (24 x^{2} + 4 x)

Solution steps

\frac{d}{d x} ((8 x^{3} + 2 x^{2})^{4})

Apply the chain rule:

4 (8 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (8 x^{3} + 2 x^{2})

= 4 (8 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (8 x^{3} + 2 x^{2})

\frac{d}{d x} (8 x^{3} + 2 x^{2}) = 24 x^{2} + 4 x

= 4 (8 x^{3} + 2 x^{2})^{3} (24 x^{2} + 4 x)

\int_{- 4}^{4} 16 - x^{2} d x

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21 x y^{^{'}} - ln (x^{7}) = 0

\int \frac{2 x}{( x ^{2} + 5 ) ln ( x ^{2} + 5 )} d x

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What is the derivative of (8x^3+2x^2)^4 ?
The derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)
What is the first derivative of (8x^3+2x^2)^4 ?
The first derivative of (8x^3+2x^2)^4 is 4(8x^3+2x^2)^3(24x^2+4x)