What is the solution for (dy)/(dx)=((2x(y-1))/(x^2+3)),y(1)=9 ?

The solution for (dy)/(dx)=((2x(y-1))/(x^2+3)),y(1)=9 is y=2x^2+7

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(dy)/(dx)=((2x(y-1))/(x^2+3)),y(1)=9

\frac{d y}{d x} = (\frac{2 x ( y - 1 )}{x ^{2} + 3}), y (1) = 9

y = 2 x^{2} + 7

Solution steps

\frac{d y}{d x} = (\frac{2 x ( y - 1 )}{x ^{2} + 3})

Solve separable ODE:

y = 2 x^{2} + 7

y = 2 x^{2} + 7

\frac{d ^{2}}{d x ^{2}} (x^{4})

(x + 2 y) d y = d x

\frac{d}{d x} (x \cdot e^{\frac{1}{x}})

x \to 1 lim (x (1))

\int_{4}^{8} \frac{2}{x ^{3}} d x

What is the solution for (dy)/(dx)=((2x(y-1))/(x^2+3)),y(1)=9 ?
The solution for (dy)/(dx)=((2x(y-1))/(x^2+3)),y(1)=9 is y=2x^2+7