What is the solution for x(dy)/(dx)+y=-9xy^2 ?

The solution for x(dy)/(dx)+y=-9xy^2 is y= 1/(x(9ln(x)+c_{1))}

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x(dy)/(dx)+y=-9xy^2

x \frac{d y}{d x} + y = - 9 x y^{2}

y = \frac{1}{x ( 9 ln ( x ) + c _{1} )}

Solution steps

x \frac{d y}{d x} + y = - 9 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( 9 ln ( x ) + c _{1} )}

y = \frac{1}{x ( 9 ln ( x ) + c _{1} )}

\frac{\partial}{\partial x} (\frac{8}{x ^{2}})

\int \frac{1}{1 - 6 x} d x

f (x) = 3 x^{2} + x + 5

f (x) = - 5 x^{2} + 2 x - 6

x \to 0 + lim (\frac{∣ x - 0 ∣}{0 - x})

What is the solution for x(dy)/(dx)+y=-9xy^2 ?
The solution for x(dy)/(dx)+y=-9xy^2 is y= 1/(x(9ln(x)+c_{1))}