What is area f(x)=-x^2+4,y+2x-4=0 ?

The answer to area f(x)=-x^2+4,y+2x-4=0 is 4/3

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area f(x)=-x^2+4,y+2x-4=0

area

f (x) = - x^{2} + 4, y + 2 x - 4 = 0

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

Isolate

y

for

y + 2 x - 4 = 0 : y = - 2 x + 4

Apply the area formula:

\int_{0}^{2} - 2 x + 4 - (- x^{2} + 4) d x

Solve

\int_{0}^{2} - 2 x + 4 - (- x^{2} + 4) d x : \frac{4}{3}

The area is:

= \frac{4}{3}

7 - 3 x

\int_{\frac{1}{2}}^{2} \frac{1}{x ^{2}} d x

e^{x}, e^{4 x}, [0, 1]

x^{3} + 2 x

\int \frac{2}{e ^{4 x}} d x

What is area f(x)=-x^2+4,y+2x-4=0 ?
The answer to area f(x)=-x^2+4,y+2x-4=0 is 4/3