What is (\partial)/(\partial θ)(ln(θ+1)) ?

The answer to (\partial)/(\partial θ)(ln(θ+1)) is 1/(θ+1)

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(\partial)/(\partial θ)(ln(θ+1))

\frac{\partial}{\partial θ} (ln (θ + 1))

\frac{1}{θ + 1}

Solution steps

\frac{\partial}{\partial θ} (ln (θ + 1))

Apply the chain rule:

\frac{1}{θ + 1} \frac{\partial}{\partial θ} (θ + 1)

= \frac{1}{θ + 1} \frac{\partial}{\partial θ} (θ + 1)

\frac{\partial}{\partial θ} (θ + 1) = 1

= \frac{1}{θ + 1} \cdot 1

Simplify

= \frac{1}{θ + 1}

\int \frac{( e ^{t a n (x)} )}{cos ^{2} ( x )} d x

y^{^{''}} + 5 y^{^{'}} + 2 y = 7

y = 2 x^{3}, (2, 16)

\int \frac{1}{x x + 1} d x

y = (\frac{x}{1 + x})^{5}

What is (\partial)/(\partial θ)(ln(θ+1)) ?
The answer to (\partial)/(\partial θ)(ln(θ+1)) is 1/(θ+1)