What is the sum from n=1 to infinity of (n-5)/n+5 ?

The sum from n=1 to infinity of (n-5)/n+5 is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (n-5)/n+5

n = 1 \sum \infty \frac{n - 5}{n} + 5

diverges

Solution steps

n = 1 \sum \infty \frac{n - 5}{n} + 5

Apply Series Divergence Test:

diverges

= diverges

\int \frac{x ^{2}}{x ^{2} + 6} d x

\int (e^{- \frac{1}{x ^{2}} - 3 l n (x)} \cdot 1) d x

\int \frac{( 3 x - 1 )}{x ^{2} + 9} d x

\int 3^{x} e^{x} d x

\frac{d}{d x} (sin (x) + csc (x))

What is the sum from n=1 to infinity of (n-5)/n+5 ?
The sum from n=1 to infinity of (n-5)/n+5 is diverges