What is the derivative of x^{2cos(x}) ?

The derivative of x^{2cos(x}) is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of x^{2cos(x}) ?

The first derivative of x^{2cos(x}) is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2 c o s (x)})

2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{2 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{2 c o s (x)} = e^{2 c o s (x) l n (x)}

= \frac{d}{d x} (e^{2 c o s (x) l n (x)})

Apply the chain rule:

e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

= e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

\frac{d}{d x} (2 cos (x) ln (x)) = 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{2 c o s (x) l n (x)} \cdot 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{2 c o s (x) l n (x)} = x^{2 c o s (x)}

= 2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

\frac{x}{1 + x}

y = \frac{- 1 e ^{x}}{x}, (1, - 1 e)

x^{2} y^{^{'}} + x y = 4, y (1) = 3

f (x) = 2 x^{\frac{1}{3}}

\int \frac{x ^{4}}{( 1 + x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of x^{2cos(x}) ?
The derivative of x^{2cos(x}) is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of x^{2cos(x}) ?
The first derivative of x^{2cos(x}) is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)