What is the tangent of y=(-1e^x)/x ,(1,-1e) ?

The tangent of y=(-1e^x)/x ,(1,-1e) is y=-e

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tangent of y=(-1e^x)/x ,(1,-1e)

tangent of

y = \frac{- 1 e ^{x}}{x}, (1, - 1 e)

y = - e

Solution steps

Find the slope of

y = \frac{- 1 e ^{x}}{x} : \frac{d y}{d x} = - \frac{e ^{x} x - e ^{x}}{x ^{2}}

Compute the slope of

y = \frac{- 1 e ^{x}}{x}

(1, - 1 e) : m = 0

Find the line with slope m=

0

and passing through

(1, - 1 e) : y = - e

y = - e

x^{2} y^{^{'}} + x y = 4, y (1) = 3

f (x) = 2 x^{\frac{1}{3}}

\int \frac{x ^{4}}{( 1 + x ^{2} ) ^{\frac{3}{2}}} d x

x^{3} + y^{3}

\int 6 e^{4} d x

What is the tangent of y=(-1e^x)/x ,(1,-1e) ?
The tangent of y=(-1e^x)/x ,(1,-1e) is y=-e