What is the derivative of 2e^{4x} ?

The derivative of 2e^{4x} is 8e^{4x}

What is the first derivative of 2e^{4x} ?

The first derivative of 2e^{4x} is 8e^{4x}

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\frac{d}{d x} (2 e^{4 x})

8 e^{4 x}

Solution steps

\frac{d}{d x} (2 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 2 e^{4 x} \cdot 4

Simplify

= 8 e^{4 x}

y^{^{''}} + 2 y^{^{'}} = - 8

(x + 1) y^{^{'}} = - 2 y + (x + 1)^{\frac{5}{2}}, y (0) = \frac{11}{9}

\frac{d}{d x} (0.41 x)

\frac{\partial}{\partial x} (1)

\int x^{3} e^{x^{2}} d x

What is the derivative of 2e^{4x} ?
The derivative of 2e^{4x} is 8e^{4x}
What is the first derivative of 2e^{4x} ?
The first derivative of 2e^{4x} is 8e^{4x}