What is the tangent of f(x)=x^2-9,(-4,7) ?

The tangent of f(x)=x^2-9,(-4,7) is y=-8x-25

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tangent of f(x)=x^2-9,(-4,7)

tangent of

f (x) = x^{2} - 9, (- 4, 7)

y = - 8 x - 25

Solution steps

Find the slope of

f (x) = x^{2} - 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 9

(- 4, 7) : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 7) : y = - 8 x - 25

y = - 8 x - 25

\frac{d}{d x} (\frac{x ^{2}}{7 + x})

\int_{- \infty}^{0} \frac{1}{2 - 4 x} d x

\int_{a}^{b} f (x) d x

(ln (\frac{x}{4}))^{^{'}}

\int 2 x (2 - x) d x

What is the tangent of f(x)=x^2-9,(-4,7) ?
The tangent of f(x)=x^2-9,(-4,7) is y=-8x-25