What is the derivative of 8x-x^2 ?

The derivative of 8x-x^2 is 8-2x

What is the first derivative of 8x-x^2 ?

The first derivative of 8x-x^2 is 8-2x

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\frac{d}{d x} (8 x - x^{2})

8 - 2 x

Solution steps

\frac{d}{d x} (8 x - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (x^{2}) = 2 x

= 8 - 2 x

n = 0 \sum \infty cos (n)

x \to 0 lim (e^{s i n (x^{2})})

\int (x - 1)^{2} (sin (x))^{2} d x

f (t) = 1.3 e^{0.7 t}

\int x \cdot e^{1 - x} d x