What is the derivative of 2x^3-x ?

The derivative of 2x^3-x is 6x^2-1

What is the first derivative of 2x^3-x ?

The first derivative of 2x^3-x is 6x^2-1

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derivative of

2 x^{3} - x

6 x^{2} - 1

Solution steps

\frac{d}{d x} (2 x^{3} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d x}{d x}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

= 6 x^{2} - 1

\int (3 sin (x) - 2 cos (x)) d x

n = 2 \sum \infty \frac{1}{2 ^{n - 1}}

45 x^{8} - 12 x^{5}

\frac{d}{d x} (\frac{96}{x})

11 x - 4 y x^{2} + 1 y^{^{'}} = 0

What is the derivative of 2x^3-x ?
The derivative of 2x^3-x is 6x^2-1
What is the first derivative of 2x^3-x ?
The first derivative of 2x^3-x is 6x^2-1