What is the limit as h approaches 0 of h/(sin(3h)) ?

The limit as h approaches 0 of h/(sin(3h)) is 1/3

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limit as h approaches 0 of h/(sin(3h))

h \to 0 lim (\frac{h}{sin ( 3 h )})

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

h \to 0 lim (\frac{h}{sin ( 3 h )})

Apply L'Hopital's Rule

: h \to 0 lim (\frac{1}{cos ( 3 h ) \cdot 3})

= h \to 0 lim (\frac{1}{cos ( 3 h ) \cdot 3})

Plug in the value

h = 0

= \frac{1}{cos ( 3 \cdot 0 ) \cdot 3}

cos (3 \cdot 0) \cdot 3 = 3

= \frac{1}{3}

\frac{\partial}{\partial x} (4 x^{2} - 2 y)

\frac{d}{d x} (ln ((sin (x) cos (x))^{2}))

\int x^{2} in (x) d x

\frac{d}{d x} (e^{x} y)

f (x) = sin (sin (x)), (π, 0)

What is the limit as h approaches 0 of h/(sin(3h)) ?
The limit as h approaches 0 of h/(sin(3h)) is 1/3