What is the limit as x approaches-1-of 1/(x^2+1) ?

The limit as x approaches-1-of 1/(x^2+1) is 1/2

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limit as x approaches-1-of 1/(x^2+1)

x \to - 1 - lim (\frac{1}{x ^{2} + 1})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

x \to - 1 - lim (\frac{1}{x ^{2} + 1})

Plug in the value

x = - 1

= \frac{1}{( - 1 ) ^{2} + 1}

(- 1)^{2} + 1 = 2

= \frac{1}{2}

y = e^{x}, y = e^{5 x}, x = 1

\frac{d y}{d t} = - 2 t cos (t^{2}) y + 6 t^{2} e^{- s i n (t^{2})}

\int π \cdot x d x

x \to 1 lim (x^{\frac{5}{x ^{2} - 1}})

f (x) = x arcsin (x)

What is the limit as x approaches-1-of 1/(x^2+1) ?
The limit as x approaches-1-of 1/(x^2+1) is 1/2