What is (\partial)/(\partial x)((90)/(6+x^2+y^2)) ?

The answer to (\partial)/(\partial x)((90)/(6+x^2+y^2)) is -(180x)/((6+x^2+y^2)^2)

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(\partial)/(\partial x)((90)/(6+x^2+y^2))

\frac{\partial}{\partial x} (\frac{90}{6 + x ^{2} + y ^{2}})

- \frac{180 x}{( 6 + x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{90}{6 + x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 90 \frac{\partial}{\partial x} (\frac{1}{6 + x ^{2} + y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 90 \frac{\partial}{\partial x} ((6 + x^{2} + y^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 6 + x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial x} (6 + x^{2} + y^{2})

= - \frac{1}{( 6 + x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial x} (6 + x^{2} + y^{2})

\frac{\partial}{\partial x} (6 + x^{2} + y^{2}) = 2 x

= 90 (- \frac{1}{( 6 + x ^{2} + y ^{2} ) ^{2}} \cdot 2 x)

Simplify

90 (- \frac{1}{( 6 + x ^{2} + y ^{2} ) ^{2}} \cdot 2 x) : - \frac{180 x}{( 6 + x ^{2} + y ^{2} ) ^{2}}

= - \frac{180 x}{( 6 + x ^{2} + y ^{2} ) ^{2}}

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What is (\partial)/(\partial x)((90)/(6+x^2+y^2)) ?
The answer to (\partial)/(\partial x)((90)/(6+x^2+y^2)) is -(180x)/((6+x^2+y^2)^2)