What is the derivative of 1-cos(2x+2cos^2(x)) ?

The derivative of 1-cos(2x+2cos^2(x)) is 0

What is the first derivative of 1-cos(2x+2cos^2(x)) ?

The first derivative of 1-cos(2x+2cos^2(x)) is 0

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\frac{d}{d x} (1 - cos (2 x) + 2 cos^{2} (x))

0

Solution steps

\frac{d}{d x} (1 - cos (2 x) + 2 cos^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (cos (2 x)) + \frac{d}{d x} (2 cos^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

\frac{d}{d x} (2 cos^{2} (x)) = - 2 sin (2 x)

= 0 - (- sin (2 x) \cdot 2) - 2 sin (2 x)

Simplify

= 0

\int 6 x^{13} e^{- x^{7}} d x

x \to 0 lim (\frac{4}{1 + 2 ^{\frac{1}{x}}})

\frac{d}{d x} (4 cos (4 x))

f^{^{'}} (x) = 3 x - 4, f (- 1) = \frac{13}{2}

ln (196 sin^{2} (x))

What is the derivative of 1-cos(2x+2cos^2(x)) ?
The derivative of 1-cos(2x+2cos^2(x)) is 0
What is the first derivative of 1-cos(2x+2cos^2(x)) ?
The first derivative of 1-cos(2x+2cos^2(x)) is 0