What is the derivative of y= 9/x+2sin(x) ?

The derivative of y= 9/x+2sin(x) is -9/(x^2)+2cos(x)

What is the first derivative of y= 9/x+2sin(x) ?

The first derivative of y= 9/x+2sin(x) is -9/(x^2)+2cos(x)

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derivative of

y = \frac{9}{x} + 2 sin (x)

- \frac{9}{x ^{2}} + 2 cos (x)

Solution steps

\frac{d}{d x} (\frac{9}{x} + 2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{9}{x}) + \frac{d}{d x} (2 sin (x))

\frac{d}{d x} (\frac{9}{x}) = - \frac{9}{x ^{2}}

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

= - \frac{9}{x ^{2}} + 2 cos (x)

\frac{d}{d x} ((2 - x^{2}) cos (x) + 2 x sin (x))

x \to \infty lim (5)

\frac{d}{d x} (\frac{- 8}{x})

\frac{d ^{2}}{d x ^{2}} (x^{2} + y^{2})

What is the derivative of y= 9/x+2sin(x) ?
The derivative of y= 9/x+2sin(x) is -9/(x^2)+2cos(x)
What is the first derivative of y= 9/x+2sin(x) ?
The first derivative of y= 9/x+2sin(x) is -9/(x^2)+2cos(x)