What is the derivative of p(x)=sqrt(x)-\sqrt[4]{x} ?

The derivative of p(x)=sqrt(x)-\sqrt[4]{x} is 1/(2sqrt(x))-1/(4x^{3/4)}

What is the first derivative of p(x)=sqrt(x)-\sqrt[4]{x} ?

The first derivative of p(x)=sqrt(x)-\sqrt[4]{x} is 1/(2sqrt(x))-1/(4x^{3/4)}

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derivative of

\frac{1}{2 x} - \frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - \frac{1}{4 x ^{\frac{3}{4}}}

\frac{d}{d x} ((2 - x^{2}) cos (x) + 2 x sin (x))

x \to \infty lim (5)

\frac{d}{d x} (\frac{- 8}{x})

\frac{d ^{2}}{d x ^{2}} (x^{2} + y^{2})

f (x) = x x, (1, 1)

What is the derivative of p(x)=sqrt(x)-\sqrt[4]{x} ?
The derivative of p(x)=sqrt(x)-\sqrt[4]{x} is 1/(2sqrt(x))-1/(4x^{3/4)}
What is the first derivative of p(x)=sqrt(x)-\sqrt[4]{x} ?
The first derivative of p(x)=sqrt(x)-\sqrt[4]{x} is 1/(2sqrt(x))-1/(4x^{3/4)}