What is the derivative of (-8/x) ?

The derivative of (-8/x) is 8/(x^2)

What is the first derivative of (-8/x) ?

The first derivative of (-8/x) is 8/(x^2)

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\frac{d}{d x} (\frac{- 8}{x})

\frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{- 8}{x})

Simplify

\frac{- 8}{x} : - \frac{8}{x}

= \frac{d}{d x} (- \frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 8 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 (- 1 \cdot x^{- 1 - 1})

Simplify

- 8 (- 1 \cdot x^{- 1 - 1}) : \frac{8}{x ^{2}}

= \frac{8}{x ^{2}}

\frac{d ^{2}}{d x ^{2}} (x^{2} + y^{2})

f (x) = x x, (1, 1)

\int e^{4 x} sin (5 x) d x

x \to 0 lim (\frac{4}{x} - \frac{4}{x ^{2} + x})

\frac{d y}{d x} = \frac{( 2 x y )}{x ^{2} - y ^{2}}

What is the derivative of (-8/x) ?
The derivative of (-8/x) is 8/(x^2)
What is the first derivative of (-8/x) ?
The first derivative of (-8/x) is 8/(x^2)