What is the first (3cos(t))^' ?

The first (3cos(t))^' is -3sin(t)

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(3cos(t))^'

(3 cos (t))^{^{'}}

- 3 sin (t)

Solution steps

(3 cos (t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 (cos (t))^{^{'}}

Apply the common derivative:

(cos (t))^{'} = - sin (t)

= 3 (- sin (t))

Simplify

= - 3 sin (t)

5 x + \frac{7}{x}

\frac{d}{d x} (x^{3} - 9 x + 3)

f (x) = \frac{1}{x + 2}, [3, 6]

y = sin (tan (8 x))

x \to 9 lim (\frac{1}{( x - 9 ) ^{2}})