What is area f(x)= 1/(x+2),[3,6] ?

The answer to area f(x)= 1/(x+2),[3,6] is 3ln(2)-ln(5)

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area f(x)= 1/(x+2),[3,6]

area

f (x) = \frac{1}{x + 2}, [3, 6]

3 ln (2) - ln (5)

Decimal Notation

0.47000 \dots

Solution steps

Apply the area formula:

\int_{3}^{6} \frac{1}{∣ x + 2 ∣} d x

Solve

\int_{3}^{6} \frac{1}{∣ x + 2 ∣} d x : 3 ln (2) - ln (5)

The area is:

= 3 ln (2) - ln (5)

y = sin (tan (8 x))

x \to 9 lim (\frac{1}{( x - 9 ) ^{2}})

\frac{\partial}{\partial x} (1 - x^{2} + y^{2})

x \to 0 + lim ((\frac{2}{x})^{x})

y = e^{x}, y = e^{- 3 x}, x = ln (4)

What is area f(x)= 1/(x+2),[3,6] ?
The answer to area f(x)= 1/(x+2),[3,6] is 3ln(2)-ln(5)