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Popular >

xy^'=y^2+1

Solution

x y^{^{'}} = y^{2} + 1

Solution

y = tan (ln (x) + c_{1})

Solution steps

x y^{'} (x) = y^{2} + 1

Solve separable ODE:

y = tan (ln (x) + c_{1})

y = tan (ln (x) + c_{1})

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Frequently Asked Questions (FAQ)

What is the solution for xy^'=y^2+1 ?
The solution for xy^'=y^2+1 is y=tan(ln(x)+c_{1})