What is the solution for (dy)/(dx)+3y=x+e^{-2x} ?

The solution for (dy)/(dx)+3y=x+e^{-2x} is y=(3x-1)/9+1/(e^{2x)}+(c_{1})/(e^{3x)}

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(dy)/(dx)+3y=x+e^{-2x}

\frac{d y}{d x} + 3 y = x + e^{- 2 x}

y = \frac{3 x - 1}{9} + \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

Solution steps

\frac{d y}{d x} + 3 y = x + e^{- 2 x}

Solve linear ODE:

y = \frac{3 x - 1}{9} + \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

y = \frac{3 x - 1}{9} + \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

\frac{3}{s + 2}

(\frac{x}{1 + x ^{2}})^{^{'}}

\int_{0}^{2 π} 1 d θ

4 arcsin (e^{\frac{x}{2}})

\frac{d}{d x} (y x^{2})

What is the solution for (dy)/(dx)+3y=x+e^{-2x} ?
The solution for (dy)/(dx)+3y=x+e^{-2x} is y=(3x-1)/9+1/(e^{2x)}+(c_{1})/(e^{3x)}