What is the integral from 0 to 2pi of 1 ?

The integral from 0 to 2pi of 1 is 2pi

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integral from 0 to 2pi of 1

\int_{0}^{2 π} 1 d θ

2 π

Decimal Notation

6.28318 \dots

Solution steps

\int_{0}^{2 π} 1 d θ

Integral of a constant:

\int a d x = a x

= [1 \cdot θ]_{0}^{2 π}

Simplify

= [θ]_{0}^{2 π}

Compute the boundaries:

2 π

= 2 π

4 arcsin (e^{\frac{x}{2}})

\frac{d}{d x} (y x^{2})

\frac{\partial}{\partial x} (sin (- x) cos (2 y))

x \to 0 lim (\frac{ln ( 3 x + 1 )}{x})

19 - x^{2}

What is the integral from 0 to 2pi of 1 ?
The integral from 0 to 2pi of 1 is 2pi