What is (\partial)/(\partial x)(-2ysin(x)) ?

The answer to (\partial)/(\partial x)(-2ysin(x)) is -2ycos(x)

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(\partial)/(\partial x)(-2ysin(x))

\frac{\partial}{\partial x} (- 2 y sin (x))

- 2 y cos (x)

Solution steps

\frac{\partial}{\partial x} (- 2 y sin (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - 2 y cos (x)

\int \frac{sin ( 20 t )}{sin ( 10 t )} d x

\int (3 t + 8)^{2.8} d t

\int 3 x^{5} - 5 x^{9} d x

d y = 2 t (y^{2} + 9) d t

n = 1 \sum \infty \frac{1}{n ^{\frac{4}{3}}}

What is (\partial)/(\partial x)(-2ysin(x)) ?
The answer to (\partial)/(\partial x)(-2ysin(x)) is -2ycos(x)