What is the derivative of f(x)=4x^2+9x ?

The derivative of f(x)=4x^2+9x is 8x+9

What is the first derivative of f(x)=4x^2+9x ?

The first derivative of f(x)=4x^2+9x is 8x+9

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derivative of

f (x) = 4 x^{2} + 9 x

8 x + 9

Solution steps

\frac{d}{d x} (4 x^{2} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (9 x) = 9

= 8 x + 9

\int_{- 2}^{1} 1 + (- 3)^{2} d x

\int cos^{2} (x) sin^{4} (x) d x

\int e^{- s x} \cdot x^{2} d x

- x^{2} + 9 x + 3, at x = 5

y = x^{2}, y = x, y = 0

What is the derivative of f(x)=4x^2+9x ?
The derivative of f(x)=4x^2+9x is 8x+9
What is the first derivative of f(x)=4x^2+9x ?
The first derivative of f(x)=4x^2+9x is 8x+9