What is the integral of 6x^2-5x-1 ?

The integral of 6x^2-5x-1 is 2x^3-(5x^2)/2-x+C

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integral of 6x^2-5x-1

\int 6 x^{2} - 5 x - 1 d x

2 x^{3} - \frac{5 x ^{2}}{2} - x + C

Solution steps

\int 6 x^{2} - 5 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x - \int 5 x d x - \int 1 d x

\int 6 x^{2} d x = 2 x^{3}

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 1 d x = x

= 2 x^{3} - \frac{5 x ^{2}}{2} - x

Add a constant to the solution

= 2 x^{3} - \frac{5 x ^{2}}{2} - x + C

f (x) = (3 x - 4)^{2}

y^{^{''}} + 2 y^{^{'}} = 2 x + 3 - e^{- 2 x}

\frac{d r}{d θ} + r tan (θ) = 5 sec (θ)

\int \frac{\frac{1}{2}}{4 - 3 x ^{2}} d x

\int arcsec (y) d y

What is the integral of 6x^2-5x-1 ?
The integral of 6x^2-5x-1 is 2x^3-(5x^2)/2-x+C