What is maclaurin e^x*cos(x) ?

The answer to maclaurin e^x*cos(x) is 1+x-1/3 x^3-1/6 x^4-1/30 x^5+\ldots

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maclaurin e^x*cos(x)

maclaurin

e^{x} \cdot cos (x)

1 + x - \frac{1}{3} x^{3} - \frac{1}{6} x^{4} - \frac{1}{30} x^{5} + \dots

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( e ^{x} cos ( x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{x} cos ( x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{x} cos ( x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 2}{3 !} x^{3} + \frac{- 4}{4 !} x^{4} + \frac{- 4}{5 !} x^{5} + \dots

Refine

= 1 + x - \frac{1}{3} x^{3} - \frac{1}{6} x^{4} - \frac{1}{30} x^{5} + \dots

\int e^{- x} ln (x) d x

y = 3 x^{2} - 5 x, (2, 2)

\frac{d}{d x} (ln (\frac{x}{1 - x}))

\int (x + sin (y)) d x

f (x) = 2 x^{2} - 9

What is maclaurin e^x*cos(x) ?
The answer to maclaurin e^x*cos(x) is 1+x-1/3 x^3-1/6 x^4-1/30 x^5+\ldots