What is the tangent of y=3x^2-5x,(2,2) ?

The tangent of y=3x^2-5x,(2,2) is y=7x-12

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tangent of y=3x^2-5x,(2,2)

tangent of

y = 3 x^{2} - 5 x, (2, 2)

y = 7 x - 12

Solution steps

Find the slope of

y = 3 x^{2} - 5 x : \frac{d y}{d x} = 6 x - 5

Compute the slope of

y = 3 x^{2} - 5 x

(2, 2) : m = 7

Find the line with slope m=

7

and passing through

(2, 2) : y = 7 x - 12

y = 7 x - 12

\frac{d}{d x} (ln (\frac{x}{1 - x}))

\int (x + sin (y)) d x

f (x) = 2 x^{2} - 9

\int (\frac{x}{6})^{n} d x

\int_{0}^{l n (4)} e^{x} - e^{- 4 x} d x

What is the tangent of y=3x^2-5x,(2,2) ?
The tangent of y=3x^2-5x,(2,2) is y=7x-12