What is the derivative of f(x)=2x^2-9 ?

The derivative of f(x)=2x^2-9 is 4x

What is the first derivative of f(x)=2x^2-9 ?

The first derivative of f(x)=2x^2-9 is 4x

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derivative of

f (x) = 2 x^{2} - 9

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (9)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (9) = 0

= 4 x - 0

Simplify

= 4 x

\int (\frac{x}{6})^{n} d x

\int_{0}^{l n (4)} e^{x} - e^{- 4 x} d x

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{- t}, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial}{\partial x} (x^{2} y e^{x^{2} + y^{2}})

What is the derivative of f(x)=2x^2-9 ?
The derivative of f(x)=2x^2-9 is 4x
What is the first derivative of f(x)=2x^2-9 ?
The first derivative of f(x)=2x^2-9 is 4x