What is the integral from 0 to ln(4) of e^x-e^{-4x} ?

The integral from 0 to ln(4) of e^x-e^{-4x} is 2817/1024

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integral from 0 to ln(4) of e^x-e^{-4x}

\int_{0}^{l n (4)} e^{x} - e^{- 4 x} d x

\frac{2817}{1024}

Decimal Notation

2.75097 \dots

Solution steps

\int_{0}^{l n (4)} e^{x} - e^{- 4 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{l n (4)} e^{x} d x - \int_{0}^{l n (4)} e^{- 4 x} d x

\int_{0}^{l n (4)} e^{x} d x = 3

\int_{0}^{l n (4)} e^{- 4 x} d x = \frac{255}{1024}

= 3 - \frac{255}{1024}

Simplify

3 - \frac{255}{1024} : \frac{2817}{1024}

= \frac{2817}{1024}

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{- t}, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial}{\partial x} (x^{2} y e^{x^{2} + y^{2}})

\int \frac{x - 1}{x ^{5}} d x

\int \frac{x ^{2}}{x ^{2} - 6 x + 13} d x

What is the integral from 0 to ln(4) of e^x-e^{-4x} ?
The integral from 0 to ln(4) of e^x-e^{-4x} is 2817/1024