What is the derivative of f(θ)=4sin(θ)-θ ?

The derivative of f(θ)=4sin(θ)-θ is 4cos(θ)-1

What is the first derivative of f(θ)=4sin(θ)-θ ?

The first derivative of f(θ)=4sin(θ)-θ is 4cos(θ)-1

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derivative of

f (θ) = 4 sin (θ) - θ

4 cos (θ) - 1

Solution steps

\frac{d}{d θ} (4 sin (θ) - θ)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (4 sin (θ)) - \frac{d}{d θ} (θ)

\frac{d}{d θ} (4 sin (θ)) = 4 cos (θ)

\frac{d}{d θ} (θ) = 1

= 4 cos (θ) - 1

4 x^{2} cos (x) cot (x)

\int e^{x yz} d x

x \to 1 lim (sin (3 π x))

y + (x + 1) \frac{d y}{d x} = 2 x + 2, y (0) = 2

y^{^{'}} = - 8 x y

What is the derivative of f(θ)=4sin(θ)-θ ?
The derivative of f(θ)=4sin(θ)-θ is 4cos(θ)-1
What is the first derivative of f(θ)=4sin(θ)-θ ?
The first derivative of f(θ)=4sin(θ)-θ is 4cos(θ)-1