What is the derivative of 4x^2cos(x)cot(x) ?

The derivative of 4x^2cos(x)cot(x) is 4(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

What is the first derivative of 4x^2cos(x)cot(x) ?

The first derivative of 4x^2cos(x)cot(x) is 4(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

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derivative of

4 x^{2} cos (x) cot (x)

4 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

Solution steps

\frac{d}{d x} (4 x^{2} cos (x) cot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2} cos (x) cot (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x) cot (x)

= 4 (\frac{d}{d x} (x^{2}) cos (x) cot (x) + \frac{d}{d x} (cos (x) cot (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x) cot (x)) = - cos (x) - cot (x) csc (x)

= 4 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

\int e^{x yz} d x

x \to 1 lim (sin (3 π x))

y + (x + 1) \frac{d y}{d x} = 2 x + 2, y (0) = 2

y^{^{'}} = - 8 x y

\frac{d y}{d x} = e^{2 x - y}

What is the derivative of 4x^2cos(x)cot(x) ?
The derivative of 4x^2cos(x)cot(x) is 4(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)
What is the first derivative of 4x^2cos(x)cot(x) ?
The first derivative of 4x^2cos(x)cot(x) is 4(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)