What is the derivative of f(x)=sqrt(1-6x) ?

The derivative of f(x)=sqrt(1-6x) is -3/(sqrt(1-6x))

What is the first derivative of f(x)=sqrt(1-6x) ?

The first derivative of f(x)=sqrt(1-6x) is -3/(sqrt(1-6x))

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derivative of

f (x) = 1 - 6 x

- \frac{3}{1 - 6 x}

Solution steps

\frac{d}{d x} (1 - 6 x)

Apply the chain rule:

\frac{1}{2 1 - 6 x} \frac{d}{d x} (1 - 6 x)

= \frac{1}{2 1 - 6 x} \frac{d}{d x} (1 - 6 x)

\frac{d}{d x} (1 - 6 x) = - 6

= \frac{1}{2 1 - 6 x} (- 6)

Simplify

\frac{1}{2 1 - 6 x} (- 6) : - \frac{3}{1 - 6 x}

= - \frac{3}{1 - 6 x}

x \to 3 - lim (\frac{3 x + 4}{x - 3})

\int sec^{7} (5 x) tan (5 x) d x

\int 3 x - 7 d x

f (x) = sin (x) + cos (x), at x = 0

\frac{d}{d x} (1 - x + ln (x))

What is the derivative of f(x)=sqrt(1-6x) ?
The derivative of f(x)=sqrt(1-6x) is -3/(sqrt(1-6x))
What is the first derivative of f(x)=sqrt(1-6x) ?
The first derivative of f(x)=sqrt(1-6x) is -3/(sqrt(1-6x))